MCQ
$\lim _{x \rightarrow 2} \frac{x+x^2+x^3-14}{x-2}=$
  • 17
  • B
    15
  • C
    25
  • D
    27

Answer

Correct option: A.
17
(A)
Applying L-Hospital's Rule, we get
$\lim _{x \rightarrow 2} \frac{x+x^2+x^3-14}{x-2}=\lim _{x \rightarrow 2}\left(1+2 x+3 x^2\right)=17$

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