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2. Electrochemistry — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistry2. Electrochemistry1 Mark
MCQ
Limiting molar conductivity of $CH_3COOH$ (i.e. $\Lambda _{m\,(C{H_3}COOH)}^o$ is equal to
  • A
    $\Lambda _{m\,(C{H_3}COOH)}^o + \Lambda _{m\,(C{H_3}COONa)}^o - \Lambda _{m\,(NaOH)}^o$
  • ✓
    $\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(HCl)}^o - \Lambda _{m\,(NaCl)}^o$
  • C
    $\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(NaCl)}^o - \Lambda _{m\,(NaOH)}^o$
  • D
    $\Lambda _{m\,(NaOH)}^o + \Lambda _{m\,(NaCl)}^o - \Lambda _{m\,(C{H_3}COONa)}^o$
✓

Answer

Correct option: B.
$\Lambda _{m\,(C{H_3}COONa)}^o + \Lambda _{m\,(HCl)}^o - \Lambda _{m\,(NaCl)}^o$
b

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