MCQ
Line of sight propagation is also called as ……………. propagation.
- Asky wave
- Bground wave
- Csound wave
- ✓space wave
✓
Answer
Correct option: D.
space wave
space wave
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following type of radiations are radiated by an oscillating electric charge?
Four particles A, B, C and D with masses $m _{ A }= m , m _{ B }=2 m, m _{ C }=3 m$ and $m _{ D }=4 m$ are at the corners of a square. They have accelerations of equal magnitude with directions as shown. The acceleration of the centre of mass of the particles is:
→Two blocks A and B of masses 3m and m respectively are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in figure. The magnitudes of acceleration of A and B immediately after the string is cut, are respectively:
The three initial and final position of a man on the x-axis are given as
(i) $(-8 m, 7 m)$
(ii) $(7 m,-3 m)$ and
(iii) $(-7 m, 3 m)$
Which pair gives the negative displacement?
→(i) $(-8 m, 7 m)$
(ii) $(7 m,-3 m)$ and
(iii) $(-7 m, 3 m)$
Which pair gives the negative displacement?
The horizontal distance x and the vertical height y of a projectile at a time t are given by x = at and $y=b t^2+c t$ where a, b and c are constants The magnitude of the velocity of the projectile 1 second after it is fired is
→Which of the following is the fundamental unit?
At the highest point of the path of a projectile, its
Range of can be increased by
A particle of mass ' $m$ ' is moving in circular path of constant radius ' $r$ ' such that centripetal acceleration is varying with time ' $t$ ' as $K^2 r t^2$ where $K$ is a constant. The power delivered to the particle by the force acting on it is
→For a truck with 14 tyres, only rear 8 wheels are power driven and can produce acceleration. These 8 wheels support half the entire load. if the coefficient of friction between road and each tyre is 0.6, the maximum attainable acceleration by this truck would be
(Acceleration due to gravity = 10 $\left.ms ^{-2}\right)$
→(Acceleration due to gravity = 10 $\left.ms ^{-2}\right)$