MCQ
ll Cu(II) halides are known except the iodide. The reason for it is that:
- Aiodide is a bulky ion.
- BCu2+ oxidizes iodide to iodine.
- C$\text{Cu}^{2+}_\text{(aq)}$ has much more negative hydration enthalpy.
- DCu2+ ion has smaller size.
Explanation:
All Cu(II) halides are known except the iodine because Cu2+ oxidizes iodine to iodine.
2Cu2++ 4I−1 → 2CuI(S) + I2.
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| column $(I)$ | column $(II)$ | ||
| $(A)$ | Kohlraush law | $(i)$ | $\Lambda _{eq}^o = \Lambda _c^o + \Lambda _a^o$ |
| $(B)$ | Molar Conductivity |
$(ii)$ | $\Lambda _m = \frac{{K \times 1000}}{M}$ |
| $(C)$ | Degree of Dissociation |
$(iii)$ | $\alpha = {\Lambda _m}/\Lambda _m^o$ |
| $(D)$ | Dissociation Constant |
$(iv)$ | ${k_a} = C{\alpha ^2}/1 - \alpha $ |

