MCQ
ln Fig. the value of DE is
Image
  • A
    $5 \sqrt{2}$ units
  • B
    10 units
  • $10 \sqrt{2}$ units
  • D
    $15 \sqrt{2}$ units

Answer

Correct option: C.
$10 \sqrt{2}$ units
(C)$10 \sqrt{2}$ units
Clearly, $C D=A B=10$ units. In right triangle $D C E$, we obtain
$
\tan 45^{\circ}=\frac{C E}{C D} \Rightarrow 1=\frac{C E}{10} \Rightarrow C E=10 \text { units }
$
Again in $\triangle D C E$, we obtain
$
\sin 45^{\circ}=\frac{C E}{D E} \Rightarrow \frac{1}{\sqrt{2}}=\frac{10}{D E} \Rightarrow D E=10 \sqrt{2} \text { units }
$

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