MCQ
Main reason for brown ring test of $NO_3^-$ is
- ANegligible tendency of $FeSO_4$ to form complex
- ✓Reducing power of $FeSO_4$ to convert $NO_3^-$ to $NO$
- CDecomposition of $FeSO_4$ to give $SO_2$ gas
- DOxidising property of $FeSO_4$
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$(i)$ $\left[ M ( NCS )_{6}\right]^{(-6+ n )}$
$(ii)$ $\left[ MF _{6}\right]^{(-6+ n )}$
$(iii)$ $\left[ M \left( NH _{3}\right)_{6}\right]^{ n ^{+}}$