MCQ
Major product for the reaction is :


- A

- B

- C

- ✓







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$(I)$ $NO + Br_2 \rightleftharpoons NOBr_2 $ ........ Fast
$(II)$ $NOBr_2 + NO \rightarrow 2NOBr$ ......... Slow
The overall order of this reaction is
Given : $N -N =159\,kJ\,mol^{-1};\,\,H-H = 436\,kJ\,mol^{-1}$
$N \equiv N = {\text{ }}941{\text{ }}kJ{\text{ }}mo{l^{ - 1}}{\text{ }};{\text{ }}N-H{\text{ }} = {\text{ }}398{\text{ }}kJ{\text{ }}mo{l^{ - 1}}$ .....$kJ\,mol^{-1}$
