MCQ
Major product of above reaction is


- A

- ✓

- C

- D







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The time taken for $A$ to become $1 / 4^{\text {th }}$ of its inital concentration is twice the time taken to become $1 / 2$ of the same. Also, when the change of concentration of $B$ is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is . . . . .
