MCQ
Major product of reaction is :
- ✓
- B
- C
- D
✓
Answer
Correct option: A.
a
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Product of the reaction
→$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,C{H_2} - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{\,\,CH - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_2} - O - C{H_3}}
\end{array}\xrightarrow{{HI(excess)}}$
The compound $(X)$ is
→The shape of $SO_4^{2 - }$ ion is
→What are the hybridisation of the carbon atoms labeled $C_1$ and $C_2$, respectively in glycine?
→$C_1$ $C_2$
The enthalpy changes at $298\, K$ in successive breaking of $O -H$ bonds of $HOH$ are-
$H_2O (g) \to H(g) + OH (g), \Delta H = 498\, kJ \,mol^{-1}$
$OH (g) \to H(g) + O (g), \Delta H = 428\, kJ\, mol^{-1}$
The bond enthalpy of the $O-H$ bond is.....$kJ\, mol^{-1}$
→$H_2O (g) \to H(g) + OH (g), \Delta H = 498\, kJ \,mol^{-1}$
$OH (g) \to H(g) + O (g), \Delta H = 428\, kJ\, mol^{-1}$
The bond enthalpy of the $O-H$ bond is.....$kJ\, mol^{-1}$
$\begin{array}{*{20}{c}}
{A\xleftarrow{{HBr}}Ph - CH = C - C{H_3}\xrightarrow[{Peroxide}]{{HBr}}B,} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
→{A\xleftarrow{{HBr}}Ph - CH = C - C{H_3}\xrightarrow[{Peroxide}]{{HBr}}B,} \\
{\,\,|} \\
{\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$A$ and $B$ is
$C _{6} H _{6}$ freezes at $5.5^{\circ} C$. The temperature at which a solution $10\, g$ of $C _{4} H _{10}$ in $200\, g$ of $C _{6} H _{6}$ freeze is ...... ${ }^{\circ} C$. (The molal freezing point depression constant of $C _{6} H _{6}$ is $5.12\,{ }^{\circ} C / m .$ )
→A $0.001\,molal$ solution of $[Pt{(N{H_3})_4}C{l_4}]$ in water had a freezing point depression of ${0.0054\,^o}C$. If ${K_f}$ for water is $1.80$, the correct formulation for the above molecule is
→Match List $I$ with List $II$.
→| List $I$ | List $II$ |
| $A.$ Invertase | $I.$ Starch into maltose |
| $B.$ Zymase | $II.$ Maltose into glucose |
| $C.$ Diastase | $III.$ Glucose into ethanol |
| $D.$ Maltase | $IV.$ Cane sugar into glucose |
Choose the most appropriate answer from the options given below
Match List$-I$ with List$-II$ :
→| List$-I$ | List$-II$ |
| $A$ $H _3 O ^{+}$ | $I$ Tetrahedral |
| $B$ Acetylide anion | $II$ Linear |
| $C$ $NH _4^{+}$ | $III$ Pyramidal |
| $D$ $ClO _2^{-}$ | $IV$ Bent |
Choose the correct answer from the options given below :