MCQ
Manganese $(VI)$ has ability to disproportionate in acidic solution. The difference in oxidation states of two ions it forms in acidic solution is $...... .$
- ✓$3$
- B$2$
- C$1$
- D$4$
✓
Answer
Correct option: A.
$3$
a
$MnO _{4}^{2-}$ disproportionates in a neutral or acidic solution to give $MnO _{4}^{-}$and $Mn ^{+4}$
$MnO _{4}^{2-}$ disproportionates in a neutral or acidic solution to give $MnO _{4}^{-}$and $Mn ^{+4}$
$3 MnO _{4}^{2-}+3 H ^{+} \longrightarrow 2 MnO _{4}^{-}+ MnO _{2}+2 H _{2} O$
O.S. of $Mn$ in $MnO _{4}^{-}=+7$
O.S. of $Mn$ in $MnO _{2}=+4$
$\text { difference }=3$
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