MCQ
Mark the smallest atom
- ✓$F$
- B$Cl$
- C$Br$
- D$I$
So, Fluorine is the smallest Halogen.
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$X$ is
$\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,COOH}\\
{\,\,\,\,\,\,\,\,\,|}\\
{\mathop {N{H_3}}\limits^{\,\, \oplus } - C - H}\\
{\,\,\,\,\,\,\,\,\,\,|}\\
{\,\,\,\,\,\,\,\,\,\,R}
\end{array}\,\,\,$

${C_({graphite)}} + {O_2} \to C{O_2};\,\Delta H = - 393.4\,kJ/mole$
${C_({graphite})} \to {C_{{\rm({diamond})}}};\,\Delta H = $