MCQ
Match List $I$ with List $II$ and select the correct answer using the code given below the lists :

List $I$ List $II$
$P.\quad$ Volume of parallelopiped determined by vectors $\vec{a}, \vec{b}$ and $\overrightarrow{ c }$ is $2$ . Then the volume of the parallelepiped determined by vectors $2(\vec{a} \times \vec{b}), 3(\vec{b} \times \vec{c})$ and $(\vec{c} \times \vec{a})$ is $1.\quad$ $100$
$Q.\quad$ Volume of parallelepiped determined by vectors $\vec{a}, \vec{b}$ and $\vec{c}$ is $5$ . Then the volume of the parallelepiped determined by vectors $3(\overrightarrow{ a }+\overrightarrow{ b }),(\overrightarrow{ b }+\overrightarrow{ c })$ and $2(\overrightarrow{ c }+\overrightarrow{ a })$ is $2.\quad$ $30$
$R.\quad$ Area of a triangle with adjacent sides determined by vectors $\vec{a}$ and $\vec{b}$ is $20$ . Then the area of the triangle with adjacent sides determined by vectors $(2 \vec{a}+3 \vec{b})$ and $(\vec{a}-\vec{b})$ is $3.\quad$ $24$
$S.\quad$ Area of a paralelogram with adjacent sides determined by vectors $\vec{a}$ and $\vec{b}$ is $30$ . Then the area of the parallelogram with adjacent sides determined by vectors $(\vec{a}+\vec{b})$ and $\vec{a}$ is $4.\quad$ $60$

 Codes: $ \quad P \quad Q \quad R \quad S $

  • A
    $\quad 4 \quad 2 \quad 3 \quad 1 $
  • B
    $\quad 2 \quad 3 \quad 1 \quad 4 $
  • $\quad 3 \quad 4 \quad 1 \quad 2 $
  • D
    $\quad 1 \quad 4 \quad 3 \quad 2 $

Answer

Correct option: C.
$\quad 3 \quad 4 \quad 1 \quad 2 $
c
$(P)\quad$ $ {[\vec{a} \vec{b} \vec{c}]=2} $

$2(\vec{a} \times \vec{b}), 3(\vec{b} \times \vec{c}),(\vec{c} \times \vec{a}) $

$6[\vec{a} \times \vec{b} \quad \vec{b} \times \vec{c} \quad \vec{c} \times \vec{a}]=6[\vec{a} \vec{b} \vec{c}]^2 $

$=6 \times 4=24 $

$P \rightarrow 3 $

$(Q)$ $\quad[\vec{a} \vec{b} \vec{c}]=5$

${[3(\vec{a}+\vec{b})(\vec{b}+\vec{c}) 2(\vec{c}+\vec{a})]} $

$=6 \times 2[\vec{a} \vec{b} \vec{c}] $

$=12 \times 5=60 $

$Q \rightarrow 4$

$(R)\quad$ $\frac{1}{2} $$ |\vec{a} \times \vec{b}|=20 $
$\Delta_1  =\frac{1}{2}|(2 \vec{a}+3 \vec{b}) \times(\vec{a}-\vec{b})| $
$ =\frac{1}{2}|-2 \vec{a} \times \vec{b}-3(\vec{a} \times \vec{b})| $
$ =\frac{5}{2}|\vec{a} \times \vec{b}| $
$ =5 \times 20=100 $
$ R \rightarrow 1$
$(S)\quad$ $|\vec{a} \times \vec{b}|=30 $
$|(\vec{a}+\vec{b}) \times \vec{a}|=|\vec{b} \times \vec{a}|=30 $
$S \rightarrow 2$

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