Choose the correct answer from the options given below:
$B.$ Neutral $FeCl _3$ solution is used to test phenolic compound $(IV)$
$C.$ Alkaline chloroform solution is used to test primary amines $(II)$
$D.$ $2 KI + NaOCl + H _2 O \rightarrow NaCl + I _2+2 KOH$
Potassium iodide and sodium hypochlorite gives $\left( I _2+ KOH \right)$ which is used to test those compounds which have $image$ group (iodoform test). Hence the compound is $image$
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In the above chemical reaction, intermediate $"X"$ and reagent/condition $"A"$ are
$\mathrm{Cu}_{(\mathrm{s})}+2 \mathrm{Ag}^{+}\left(1 \times 10^{-3} \,\mathrm{M}\right) \rightarrow \mathrm{Cu}^{2+}(0.250\, \mathrm{M})+2 \mathrm{Ag}_{(\mathrm{s})}$
$\mathrm{E}_{\mathrm{Cell}}^{\ominus}=2.97\, \mathrm{~V}$
$\mathrm{E}_{\text {cell }}$ for the above reaction is $....\,V.$ (Nearest integer)
[Given : $\log 2.5=0.3979, T=298\, \mathrm{~K}]$