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STD 12 - p -Block elements - ll — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 12 - p -Block elements - ll4 Marks
MCQ
Match the compounds given in $column\, I$ with the hybridisation and shape given in $column\, II$ and mark the correct option.

 $\begin{array}{|l|l|} \hline Column\,\,I & Column\,\,II \\ \hline (A)\,XeF_6 & (i)\,\,distortedoctahedral \\ \hline (B)\,XeO_3 & (ii)\,\,square\,\,planar \\ \hline (C)\,XeOF_4 & (iii)\,\,pyramidal \\ \hline (D)\,XeF_4 & (iv)\,\,square\,\,pyramidal \\ \hline \end{array}$

  • A
    $A-(iv),B-(iii),C-(i),D-(ii)$
  • B
    $A-(iv),B-(i),C-(ii),D-(iii)$
  • ✓
    $A-(i),B-(iii),C-(iv),D-(ii)$
  • D
    $A-(i),B-(ii),C-(iv),D-(iii)$
✓

Answer

Correct option: C.
$A-(i),B-(iii),C-(iv),D-(ii)$
c
In $XeF _6$, the central $Xe$ atom undergoes $sp ^3 d ^3$ hybridisation and the molecular geometry is distorted octahedral with $1$ lone pair and $6$ bond pairs of electrons.

In $XeO _3$, the central $Xe$ atom undergoes $sp ^3$ hybridisation and the molecular geometry is pyramidal with $1$ lone pair and $3$ bonding domains of electrons.

In $XeOF _4$, the central $Xe$ atom undergoes $sp ^3 d ^2$ hybridization and the molecular geometry is square pyramidal with $1$ lone pair and $5$ bond pairs of electrons.

In $XeF _4$, the central $Xe$ atom undergoes $sp ^3 d ^2$ hybridization and the molecular geometry is square planar with $2$ lone pairs and $4$ bond pairs of electrons.

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