MCQ
$\mathop {\lim }\limits_{\alpha \to \beta } \left[ {\frac{{{{\sin }^2}\alpha - {{\sin }^2}\beta }}{{{\alpha ^2} - {\beta ^2}}}} \right] = $
- A$0$
- B$1$
- C$\frac{{\sin \beta }}{\beta }$
- ✓$\frac{{\sin 2\beta }}{{2\beta }}$
Applying $ L-$ Hospital’s rule,
$\mathop {{\rm{lim}}}\limits_{\alpha \to \beta } \frac{{2\sin \,\alpha \,\,\cos \alpha }}{{2\alpha }} = \mathop {{\rm{lim}}}\limits_{\alpha \to \beta } \frac{{\sin \,\,2\alpha }}{{2\alpha }} = \frac{{\sin \,\,2\beta }}{{2\beta }}$.
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$f(x)=(1+|\sin x|)^{\frac{3 a}{\sin x \mid}} ,\quad -\frac{\pi}{4}\,<\,x\,<\,0$
$\quad\quad\quad\quad\quad\quad b ,\quad\quad\quad\quad\quad x=0$
$\quad\quad\quad\quad e^{\cot 4 x / \cot 2 x} ,\quad\quad\quad 0\,<\,x\,<\,\frac{\pi}{4}$
If $\mathrm{f}$ is continuous at $\mathrm{x}=0$, then the value of $6 \mathrm{a}+\mathrm{b}^{2}$ is equal to: