MCQ
$\mathop {\lim }\limits_{n \to \infty } \frac{1}{2} + \frac{1}{{{2^2}}} + \frac{1}{{{2^3}}} + ... + \frac{1}{{{2^n}}}$ equals
- A$2$
- B$-1$
- ✓$1$
- D$3$
$\mathop {\lim }\limits_{n \to \infty } \,\left[ {1 - \frac{1}{{{2^n}}}} \right] = 1 - 0 = 1$
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($1$) The value of $\frac{625}{4} p _1$ is
($2$) The value of $\frac{125}{4} p _2$ is
Give the answer or queution ($1$) and ($2$)