MCQ
$\mathop {\lim }\limits_{x \to 0} $ $\frac{{\int\limits_0^x ( {\text{ta}}{{\text{n}}^{ - 1}}{\text{ t }}{{\text{)}}^2}{\text{dt}}}}{{({\text{sinx - x}})}}$ is-
  • A
    $0$
  • $-2$
  • C
    $2$
  • D
    $\frac{1}{2}$

Answer

Correct option: B.
$-2$
b
$-2$

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