MCQ
$\mathop {\lim }\limits_{x \to 0} \,\,\frac{{{{\log }_e}(1 + x)}}{{{3^x} - 1}} = $
- A${\log _e}3$
- B$0$
- C$1$
- ✓${\log _3}e$
Using $ L-$ Hospital’s rule,
$\mathop {\lim }\limits_{x \to 0} \frac{{\frac{1}{{1 + x}}}}{{{3^x}{{\log }_e}3}} = \frac{1}{{{{\log }_e}3}} = {\log _3}e$.
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