MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{\sin (\pi {{\cos }^2}x)}}{{{x^2}}} = $
- A$( - 1,1)$
- ✓$\pi $
- C$\pi /2$
- D$1$
$ = \mathop {{\rm{lim}}}\limits_{x \to 0} \pi \cos (\pi {\cos ^2}x).\cos x.\left( {\frac{{ - \sin x}}{x}} \right)$
$ = \pi ( - 1).1.( - 1) = \pi $.
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