MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{x\cos x - \sin x}}{{{x^2}\sin x}} = $
- A$\frac{1}{3}$
- ✓$ - \frac{1}{3}$
- C$1$
- Dએકપણ નહી.
$ = \mathop {\lim }\limits_{x \to 0} \,\,\frac{{ - \sin x}}{{2\sin x + x\cos x}}$
(By $L-$ Hospital’s rule)
$ = \mathop {\lim }\limits_{x \to 0} \,\,\frac{{ - \cos x}}{{3\cos x - x\sin x}} = - \frac{1}{3}$,
(Again by $L-$ Hospital’s rule)
$ = - \frac{1}{3}$
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વિસ્તરણમાં $\alpha ^t$ નો સહગુણક મેળવો.
જ્યાં $\alpha \ne - q$ અને $p \ne q$