MCQ
$\mathop {\lim }\limits_{x \to 3} \,[x] = $, (where $[.] =$ greatest integer function)
  • A
    $2$
  • B
    $3$
  • Does not exist
  • D
    None of these

Answer

Correct option: C.
Does not exist
c
(c) $\mathop {\lim }\limits_{h \to {0^ + }} \,[3 + h] = 3$ and $\mathop {\lim }\limits_{h \to {0^ - }} \,[3 - h] = 2$

$\therefore$ $\mathop {\lim }\limits_{x \to 3} \,\,[x]$ does not exist.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Given that $\pi < \alpha < \frac{{3\pi }}{2},$ then the expression $\sqrt {(4{{\sin }^4}\alpha + {{\sin }^2}2\alpha )} + 4{\cos ^2}\left( {\frac{\pi }{4} - \frac{\alpha }{2}} \right)$ is equal to
Let $\mathrm{A}(\mathrm{x}, \mathrm{y}, \mathrm{z})$ be a point in xy-plane, which is equidistant from three points $(0,3,2),(2,0,3)$ and $(0,0,1)$.
Let $\mathrm{B}=(1,4,-1)$ and $\mathrm{C}=(2,0,-2)$. Then among the statements
(S1): $\triangle \mathrm{ABC}$ is an isosceles right angled triangle and
(S2) : the area of $\triangle \mathrm{ABC}$ is $\frac{9 \sqrt{2}}{2}$.
The equation of motion of a stone, thrown vertically upwards is $s = ut - 6.3{t^2},$ where the units of $s $ and $t $ are $cm$ and $sec.$ If the stone reaches at maximum height in $3$ sec, then  $u  =$ ......... $cm/\sec $
If the point dividing internally the line segment joining the points $(a, b)$ and $(5, 7)$ in the ratio $2 : 1$ be $(4, 6)$, then
The sum of the series $\frac{1}{x+1}+\frac{2}{x^{2}+1}+\frac{2^{2}}{x^{4}+1}+\ldots . .+\frac{2^{100}}{x^{2^{100}}+1}$ when $x=2$ is :
If $1 - i$ is a root of the equation ${x^2} - ax + b = 0$, then $b = $
Two students while solving a quadratic equation in $x$, one copied the constant term incorrectly and got the roots $3$ and $2$. The other copied the constant term and coefficient of ${x^2}$ correctly as $-6$ and $1$ respectively. The correct roots are
Suppose the parabola $(y-h)^2=4(x-h)$, with vertex $A$, passes through $O=(0,0)$ and $L=(0,2)$. Let $D$ be an end point of the latusrectum. Let the $Y$-axis intersect the axis of the parabola at $P$. Then, $\angle P D A$ is equal to
If $1,\omega ,{\omega ^2}$ are the cube roots of unity, then $\Delta = \left| {\,\begin{array}{*{20}{c}}{1\,\,\,\,}&{{\omega ^n}}&{{\omega ^{2n}}}\\{{\omega ^n}\,\,}&{\,\,\,{\omega ^{2n}}\,\,}&1\\{{\omega ^{2n}}\,}&{1\,\,}&{{\omega ^n}}\end{array}} \right|$=
Let $x$ be the length of one of the equal sides of an isosceles triangle, and let $\theta$ be the angle between them. If $x$ is increasing at the rate $(1/12) \,\,m/hr$, and $\theta$ is increasing at the rate of $\pi /180 \,\,radians/hr$ then the rate in $m^2\,/hr$ at which the area of the triangle is increasing when $x = 12\, m$ and $\theta = \pi /4$