Download App

STD 11 - 12. limits — JEE STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceJEESTD 11 - 12. limits4 Marks
MCQ
$\mathop {\lim }\limits_{x \to \infty } \frac{{(x - 1)(2x + 3)}}{{{x^2}}} = $
  • A
    $1$
  • B
    $-1$
  • ✓
    $2$
  • D
    None of these
✓

Answer

Correct option: C.
$2$
c
(c) $\mathop {\lim }\limits_{x \to \infty } \,\,\frac{{(x - 1)\,\,(2x + 3)}}{{{x^2}}} = \mathop {\lim }\limits_{x \to \infty } \,\,\frac{{2{x^2} + x - 3}}{{{x^2}}} = 2.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Let the volume of a parallelopiped whose coterminous edges are given by $\overrightarrow{\mathrm{u}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}+\lambda \hat{\mathrm{k}}, \overrightarrow{\mathrm{v}}=\hat{\mathrm{i}}+\hat{\mathrm{j}}+3 \hat{\mathrm{k}} $ and $\overrightarrow{\mathrm{w}}=2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}$ be $1\; cu.$ unit. If $\theta$ be the angle between the edges $\overrightarrow{\mathrm{u}}$ and $\overrightarrow{\mathrm{w}},$ then $\cos \theta$ can be
→
If the coefficient of ${x^7}$ in ${\left( {a{x^2} + \frac{1}{{bx}}} \right)^{11}}$ is equal to the coefficient of ${x^{ - 7}}$ in ${\left( {ax - \frac{1}{{b{x^2}}}} \right)^{11}}$, then $ab =$
→
Let $f:\left[ {0,2} \right] \to R$ be a twice differentiable function such that $f''\left( x \right) > 0$, for all $x \in \left( {0,2} \right)$. If $\phi \left( x \right) = f\left( x \right) + f\left( {2 - x} \right)$, then $\phi $ is
→
If $a, b$ and $c$ are the three non-coplanar vectors, then $(a + b + c)\,.\,[(a + b) \times (a + c)]$ is equal to
→
The $\mathop {\lim }\limits_{x \to 0} {(\cos x)^{\cot x}}$ is
→
For $x \in R$, then number of real roots of the equation $3 x^2-4\left|x^2-1\right|+x-1=0$ is. . . . . .
→
The sum of the first three terms of a $G.P.$ is $S$ and their product is $27 .$ Then all such $S$ lie in 
→
The points of intersection of the curves whose parametric equations are $x = {t^2} + 1,\;y = 2t$ and $x = 2s,\;y = \frac{2}{s}$ is given by
→
$1\, + \,\frac{{{1^3}\, + \,{2^3}}}{{1 + 2}} + \frac{{{1^3}\, + \,{2^3} + {3^3}}}{{1 + 2 + 3}} + ...... + \frac{{{1^3}\, + \,{2^3} + {3^3} + ..... + {{15}^3}}}{{1 + 2 + 3 + ..... + 15}} - \frac{1}{2}\left( {1 + 2 + 3 + ....+15} \right)$ is equal to
→
Two cards are drawn successively with replacement from a well shuffled deck of $52$ cards then the mean of the number of aces is
→