MCQ
$\mathop {\lim }\limits_{x \to \infty } {\left( {1 + \frac{2}{x}} \right)^x} = $
  • A
    $e$
  • B
    $\frac{1}{e}$
  • ${e^2}$
  • D
    None of these

Answer

Correct option: C.
${e^2}$
c
(c)${\left[ {\mathop {\lim }\limits_{x \to \infty } {{\left( {1 + \frac{1}{{x/2}}} \right)}^{x/2}}} \right]^2} = {e^2}.$

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