- A$x tan^{-1}(x)$
- B$tan^{-1}(x)$
- ✓$\frac{{{{\tan }^{ - 1}}(x)}}{x}$
- D$\frac{{{{\tan }^{ - 1}}(x)}}{{{x^2}}}$
$S=\frac{1}{n} \sum_{k=1}^{n} \frac{1}{1+\underbrace{(k / n)^{2} x^{2}}}_{1}=\int_{0}^{1} \frac{d t}{1+t^{2} x^{2}}$
$=\frac{1}{x^{2}} \int_{0}^{1} \frac{d t}{t^{2}+\left(1 / x^{2}\right)}=\left[\frac{1}{x} \tan ^{-1}(t x)\right]_{0}^{1}=\frac{\tan ^{-1}(x)}{x}$
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(where $c$ is a constant of integration)
$\frac{1}{3\ln\text{x}}$
$\frac{1}{3\ln\text{x}}-\frac{1}{2\ln\text{x}}$
$\big(\ln\text{x}\big)^{-1}\text{x}(\text{x}-1)$
$\frac{3\text{x}^2}{\ln\text{x}}$
$\mathrm{f}(\mathrm{x})= \int_{0}^{x}[y] \,d y$
Where $[x]$ is the greatest integer less than or equal to $x$. Which of the following is true?
$\begin{bmatrix} -\text{d} & -\text{b} \\ -\text{c} & \text{a} \end{bmatrix}$
$\begin{bmatrix} \text{d} & -\text{b} \\ -\text{c} & \text{a} \end{bmatrix}$
$\begin{bmatrix} \text{d} & \text{b} \\ \text{c} & \text{a} \end{bmatrix}$
$\begin{bmatrix} \text{d} & \text{c} \\ \text{b} & \text{a} \end{bmatrix}$