MCQ
Maximum oxidation state is snown by
- ✓$Os$
- B$Mn$
- C$Cr$
- D$Co$
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The final product formed in the above reaction sequence is
$\underset{{{C}_{3}}{{H}_{6}}C{{l}_{2}}}{\mathop{A}}\,\,\xrightarrow[2.\,\,{{H}^{+}}\,\,(\min d)]{\begin{smallmatrix}
1\,.\,\,alcoholic\,\,KOH\,/\,\Delta \\
followed\,\,by\,\,NaN{{H}_{2}}\,/\,\Delta
\end{smallmatrix}}$ $B\,\xrightarrow[{{H}_{2}}{{O}_{2}}/\overset{\Theta }{\mathop{O}}\,H]{{{B}_{2}}{{H}_{6}}}C$
$A\,\xrightarrow{aq.\,\,KOH\,(excess)}C$
What is $''B''$ ?