- A$Mg_2\,C_3,Be_2\,C, Al_4\,C_3$ and $CaC_2$
- B$Mg_2\,C_3, Be_2\,C$ and $Al_4\,C_3$
- C$Be_2\,C, Al_4\,C_3$ and $CaC_2$
- ✓$Be_2\,C$ and $Al_4\,C_3$
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Statement $I$ : The correct order of first ionization enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{Cl}<\mathrm{F}$.
Statement $II$ : The correct order of negative electron gain enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{F}<\mathrm{Cl}$
In the light of the above statements, choose the correct answer from the options given below :
Which conformer of above compound is most stable (consider conformer across $(C_2 -C_3)$
$L(1s^2, 2s^2 2p^4); Q(1s^2, 2s^2 2p^6, 3s^2 3p^5)$
$P(1s^2, 2s^2 2p^6, 3s^1); R(1s^2, 2s^2 2p^6, 3s^2)$
The formulae of ionic compounds that can be formed between these elements are