MCQ
Methanol and ethanol are miscible in water due to
  • A
    Covalent character
  • Hydrogen bonding character
  • C
    Oxygen bonding character
  • D
    None of these

Answer

Correct option: B.
Hydrogen bonding character
b
Methanol and ethanol contain polar covalent $O - H$ bond. Hence, they can form hydrogen bonds. Due to their hydrogen bonding character, they are miscible with water.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The compound($s$) with $TWO$ lone pairs of electrons on the central atom is(are)

($A$) $\mathrm{BrF}_5$ ($B$) $\mathrm{ClF}_3$ ($C$) $\mathrm{XeF}_4$  ($D$) $\mathrm{SF}_4$

Oxidation number of iodine varies from
An ideal gas is expanded from $1 \times 10^{-3} \,m^3$ to $1 \times 10^{-2} \,m^3$ against constant pressure of $1 \times 10^5\, N/m^2$ at $300\, K$. The work done is
In a compound the ratio of masses of $H,C,O$ and $N$ is $1:3:4:7$. The empirical formula is
The increasing order of basicity for the following intermediates is (from weak to strong)

$(i)$ $\begin{array}{*{20}{c}}
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {C{H_3} - {C^ \mathbf{-} }} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\ 
  {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} 
\end{array}$

$(ii)$ $H _{2} C = CH - CH _{2}$

$(iii)$ $HC \equiv \stackrel{\ominus}{ C }$

$(iv)$ $\stackrel{\ominus}{ CH _{3}}$

$(v)$ $\stackrel{\ominus}{{ }_{ CN }}$

Total number of isomeric compounds (including stereoisomers) formed by monochlorination of $2-$methylbutane is................ 
$20\,mL$ of $0.02\,M\,K _{2} Cr _{2} O _{7}$ solution is used for the titration of $10 \,mL$ of $Fe ^{2+}$ solution in the acidic medium.The molarity of $Fe ^{2+}$ solution is ........... $\times 10^{-2}\,M$ (Nearest Integer)
Among the following least and most metallic element will be respectively :
$(I)$ $[He]\, 2s^1$           $(II)$ $[Kr]\,5s^2\,4d^{10}\,5p^5$
$(III)$ $[Xe]\,6s^1$          $(IV)$ $[He]\,2s^2\,2p^5$
Electronic configurations of four elements A, B, C and D are given below:

A. $1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6$   B. $1\text{s}^2\ 2\text{s}^2\ 2\text{p}^4$   C.$1\text{s}^2\ 2\text{s}^2\ 2\text{p}^6\ 3\text{s}^1$   D.$1\text{s}^2\ 2\text{s}^2\ 2\text{p}^5$

Which of the following is the correct order of increasing tendency to gain electron:

From the given sets of quantum numbers the one that is inconsistent with the theory is