MCQ
Molar concentration $(M)$ of any solution $=$
  • $\frac{{{\rm{No}}\,{\rm{. of \,moles\, of\, solute}}}}{{{\rm{Volume\, of \,solution\, in\, litre}}}}$
  • B
    $\frac{{{\rm{No}}{\rm{. \,of \,gram\, equivalent \,of \,solute}}}}{{{\rm{Volume \,of \,solution\, in \,litre}}}}$
  • C
    $\frac{{{\rm{No}}{\rm{. \,of \,moles\, of\, solute}}}}{{{\rm{Mass \,of \,solvent \,in\, kg}}}}$
  • D
    $\frac{{{\rm{No}}{\rm{. \,of\, moles \,of \,any \,constituent}}}}{{{\rm{Total\, no}}{\rm{.\, of \,moles \,of \,all \,constituents}}}}$

Answer

Correct option: A.
$\frac{{{\rm{No}}\,{\rm{. of \,moles\, of\, solute}}}}{{{\rm{Volume\, of \,solution\, in\, litre}}}}$
a
Molarity $(M)$ is defined as the number of moles of solute per liter of solution.

$\text { molarity }=\frac{\text { moles of solute }}{\text { volume of solution in litre. }}$

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