MCQ
Molecular formula of amyl alcohol is
- A${C_7}{H_{14}}O$
- B${C_6}{H_{13}}O$
- ✓${C_5}{H_{12}}O$
- D${C_5}{H_{10}}O$
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$\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HOCH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\I\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HOCH}\\|\\{C{H_2}OH}\\{II}\end{array}$ $\begin{array}{*{20}{c}}{CHO}\\|\\{HCOH}\\|\\{HCOH}\\|\\{HCOH}\\|\\{C{H_2}OH}\\{III}\end{array}$
(The atomic mass of $Na$ is $23\, g / mol$ ) :
compound will be: