Question
Molecular mass of nitric acid is:

Answer

Molecular mass of nitric acid $(\ce{HNO3​}) = (1 \times $ atomic mass of $H) + (1 \times $ atomic mass of $N) + (3 \times $ atomic mass of $O)$
$= 1 \times (1u) + 1 \times (14u) + 3 \times (16u)$
$= 63u$

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