MCQ
Most acidic among given compound is
- A$Pr(OH)_3$
- B$Gd(OH)_3$
- C$Sm(OH)_3$
- ✓$Er(OH)_3$
✓
Answer
Correct option: D.
$Er(OH)_3$
d
In lanthanoids hydroxides on moving left to right acidic nature increases.
In lanthanoids hydroxides on moving left to right acidic nature increases.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Which of the following is not the characteristic of ionic solids?
The only alcohol that can be prepared by the indirect hydration of alkene is:
As regards the use of international food safety standards as reference point for the dispute settlements, which one of the following does $\text{WTO}$ collaborate with?
→In the following compounds
The order of acidity is
Which of the following reaction would be incorrect ?
Which of the following amines reacts most rapidly with
Which of the following complex ions is expected to absorb visible light ?
→[At. nos. $Zn = 30, Sc = 21, $$Ti = 22, Cr = 24$]
Triple degenerate $d-$ orbitals are exactly half-filled in
→For an electrochemical cell
→$\mathrm{Sn}(\mathrm{s})\left|\mathrm{Sn}^{2+}(\mathrm{aq}, 1 \mathrm{M}) \| \mathrm{Pb}^{2+}(\mathrm{aq}, 1 \mathrm{M})\right| \mathrm{Pb}(\mathrm{s})$
the ratio $\frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{Pb}^{2+}\right]}$ when this cell attains equilibrium is
(Given $\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{0}=-0.14 \mathrm{\;V}$ $\left.\mathrm{E}_{\mathrm{Pb}^{+2}/{\mathrm{Pb}}}^{0}=-0.13 \;\mathrm{V}, \frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.06\right)$
An aqueous solution is $1.00$ molal in $KI.$ Which change will cause the vapour pressure of the solution to increase ?
→