MCQ
Most stable carbonium ion is
- A${\mathop C\limits^ + _2}{H_5}$
- B${(C{H_3})_3}\mathop C\limits^ + $
- ✓${({C_6}{H_5})_3}\mathop C\limits^ + $
- D${C_6}{H_5}\mathop C\limits^ + {H_2}$
✓
Answer
Correct option: C.
${({C_6}{H_5})_3}\mathop C\limits^ + $
c
(c)In the triphenyl methyl carbonium ion the $\pi$ electrons of all the three benzene rings are delocalised with the vacant $p-$orbital of central carbon atom. So, it is resonance stabilised. It is the most stable of all the carbonium ions given
(c)In the triphenyl methyl carbonium ion the $\pi$ electrons of all the three benzene rings are delocalised with the vacant $p-$orbital of central carbon atom. So, it is resonance stabilised. It is the most stable of all the carbonium ions given
The ion $C{H_3} - \mathop {\mathop {{C^ + }}\limits_{|\;\;}^{|\;\;} \;\;}\limits_{C{H_3}}^{C{H_3}} $ is stabilised by hyperconjugation, a second order resonance.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If solubility product of $Z{r_3}{\left( {P{O_4}} \right)_4}$ is denoted by $K_{SP}$ and its molar solubility is denoted by $S$, then which of the following relation between $S$ and $K_{SP}$ is correct?
→Formula which represents a simple ratio of atoms of different elements present in a molecule of the substance is called
The following reaction occurs in the Blast furnance where iron ore is reduced to iron metal
→$\mathrm{Fe}_2 \mathrm{O}_{3(\mathrm{~s})}+3 \mathrm{CO}_{(\mathrm{g})} \rightleftharpoons \mathrm{Fe}_{(1)}+3 \mathrm{CO}_{2(\mathrm{~g})}$
Using the Le-chatelier's principle, predict which one of the following will not disturb the equilibrium.
Which is amphoteric oxides ?
Select correct about the following change
→$NO_2^ + \to N{O_2} \to NO_2^ - $
An element forms two oxides containing respectively $53.33$ and $36.36$ percent of oxygen. These figures illustrate the law of
→→
The electrons identified by quantum numbers $n$ and $l$ $(i)$ $n = 4,\,l = 1$ $(ii)$ $n = 4,\,l = 0$ $(iii)$ $n = 3,\,l = 2$ $(iv)$ $n = 3,\,l = 1$ can be placed in order of increasing energy from the lowest to highest, as
→If 1mL of water contains 20 drops then number of molecules in a drop of water is:
The total number of orbitals present for principle quantum number, $n=4$ is
→