Question
Multiply:
$12\sqrt{15}$ by $4\sqrt{3}$
$12\sqrt{15}$ by $4\sqrt{3}$
✓
Answer
$12\sqrt{15}$ by $4\sqrt{3}$
$12\sqrt{15}\div4\sqrt{3}=\frac{12\sqrt{15}}{4\sqrt{3}}=\frac{3\sqrt{15}}{\sqrt{3}}=\frac{3\sqrt{15}\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}$
$=\frac{3\sqrt{15\times3}}{3}=\sqrt{3\times5\times3}=3\sqrt{5}$
$12\sqrt{15}\div4\sqrt{3}=\frac{12\sqrt{15}}{4\sqrt{3}}=\frac{3\sqrt{15}}{\sqrt{3}}=\frac{3\sqrt{15}\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}$
$=\frac{3\sqrt{15\times3}}{3}=\sqrt{3\times5\times3}=3\sqrt{5}$
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Read the Source/ Text given below and answer these questions:
In the above picture, one small square is of size 1km × 1km. From the starting point O(0, 0) Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home. From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2km. He found a hospital in the way. From Hospital he drove 3km and finally reached his school.
questions:
1. What is the common ordinate of temple and Zoo?
2. Deepak Drove in which quadrants?
In the above picture, one small square is of size 1km × 1km. From the starting point O(0, 0) Deepak started to drive towards his home. He first drives 3km in left then he turned to his left and drove 2km, there he found a temple. He worshipped there and drove 6km in the left direction, there is a zoo and from the zoo, he drives 2km on the right side, then he reached his home. From O Sanjay drove for his school, he drove 1km to his right then took a left turn and drives 2km then again took a right turn and drives 2km. He found a hospital in the way. From Hospital he drove 3km and finally reached his school.
questions:
1. What is the common ordinate of temple and Zoo?
2. Deepak Drove in which quadrants?