Question
Multiply: $-\frac{3}{2} x^5 y^3$ and $\frac{4}{9} a^2 x^ 3 y$

Answer

$ \left(-\frac{3}{2} x^5 y^3\right)\left(\frac{4}{9} a^2 x^3 y\right)$
$ =\left(-\frac{3}{2} \times \frac{4}{9}\right)\left(a^2\right)\left(x^5 \times x^3\right)\left(y^3 \times y\right)$
$ =\frac{-2}{3} a^2 x^8 y^4$

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