- ARacemization
- Boptical resolution
- Cconformational inversion
- ✓Diastereoisomerization
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$(A)$ Internal energy $(B)$ Irreversible expansion work
$(C)$ Reversible expansion work $(D)$ Molar enthalpy
for the above reaction at $298 K , K _{ c }$ is found to be $3.0 \times 10^{-59}$. If the concentration of $O _{2}$ at equilibrium is $0.040 M$ then concentration of $O _{3}$ in $M$ is ...... .
$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
Statement $I$: The boiling point of hydrides of Group $16$ elements follow the order
$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{~S}$.
Statement $II$: On the basis of molecular mass, $\mathrm{H}_2 \mathrm{O}$ is expected to have lower boiling point than the othe members of the group but due to the presence of extensive $\mathrm{H}$-bonding in $\mathrm{H}_2 \mathrm{O}$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
|
List$-I$ (Species) |
List$-II$ (Hybrid Orbitals) |
| $(a)$ $\mathrm{SF}_{4}$ | $(i)$ $\mathrm{sp}^{3} \mathrm{~d}^{2}$ |
| $(b)$ $\mathrm{IF}_{5}$ | $(ii)$ $\mathrm{d}^{2} \mathrm{sp}^{3}$ |
| $(c)$ $\mathrm{NO}_{2}^{+}$ | $(iii)$ $\mathrm{sp}^{3} \mathrm{~d}$ |
| $(d)$ $\mathrm{NH}_{4}^{+}$ | $(iv)$ $\mathrm{sp}^{3}$ |
| $(v)$ $\mathrm{sp}$ |
Choose the correct answer form the options given below :
$(A)$ $\begin{matrix}
O\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\, \\
R-C-NHBr \\
\end{matrix}$ $(B)$ $R-NH-Br$
$(C)$ $R-N=C=O$ $(D)$ $\begin{matrix}
\,\,\,\,O\,\,\,\,\,\,\,\,\,\, \\
\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\, \\
R-C-NB{{r}_{2}} \\
\end{matrix}$