MCQ
N identical spherical drops charged to the same potential V are combined to form a big drop. The potential of the new drop will be
- AV
- BV/N
- CV × N
- ✓$V ×{N}^{2 / 3}$
✓
Answer
Correct option: D.
$V ×{N}^{2 / 3}$
(d)$V ×{N}^{2 / 3}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In given figure, the potentiometer wire AB has a resistance of 5 W and length 10 m. The balancing length AM for the emf of 0.4 V is
The potential difference between the plates of a parallel plate capacitor is changing at the rate of $10^6\, V/s$. If the capacitance is $2\,\mu F$, the displacement current in the dielectric of the capacitor will be......$A$
→When the number of nucleons in a nucleus increases, the binding energy per nucleon:
At a place, the magnitudes of the horizontal component and total intensity of the magnetic field of the earth are $0.3 $ and $ 0.6$ Oersted respectively. The value of the angle of dip at this place will be.....$^o$
→Assertion : Neutrons penetrate mater more readily as compared to protons.
Reason : Neutrons are slightly more massive than protons.
In Young's double slit experiment, a glass plate is placed before a slit which absorbs half the intensity of light. Under this case
If radius of the $^{27}_{13}Al$ nucleus is taken to be $R_{Al}$, then the radius of $^{125}_{53}Te$ nucleus is nearly
→A small rod of length $2\,mm$ lies along principal axis at a distance of $30\, cm$ from a concave mirror of focal length $20\, cm$ than the axial length of the image of the rod is.....$mm$
→The wavelength of light visible to eye is of the order of:
If a wire of length 1 meter placed in uniform magnetic field 1.5 Tesla at angle 30° with magnetic field. The current in a wire 10 amp. Then force on a wire will be