MCQ
$\ce{Na_2SO_3}⋅\ce{xH_2O}$ has $50\%\ \ce{H_2O}$ by mass. Hence $, x$ is :
- A$4$
- B$5$
- C$6$
- ✓$7$
✓
Answer
Correct option: D.
$7$
Molecular mass of $\ce{Na_2SO_3}⋅ \ce{x H_2 O = 126 + 18x}$
Hence, $\frac{18\text{x}}{126+18\text{x}}=0.5{\text{(given)}}$
$\therefore\text{x}=7$
Hence, $\frac{18\text{x}}{126+18\text{x}}=0.5{\text{(given)}}$
$\therefore\text{x}=7$
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