MCQ
$NH _{3}$ reacts with bleaching powder to given :
- ✓$N _{2}$
- B$Ca ( OH )_2$
- C$NCl _{3}$
- D$O _{2}$
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Codes: $ \quad P \quad Q \quad R \quad S $

hence $A$ $\xrightarrow{{conc.\,{H_2}S{O_4}}}$ $B,$ $B$ is :