MCQ
$(NH_4 )_2Cr _2O_7$ on heating liberates a gas. The same gas will be obtained by
- ✓Heating $NH_4NO_2$
- BHeating $NH_4NO_3$
- CHeating $(NH_4)_2SO_4$
- DTreating $Mg_3N_2$ with $H _2O$
✓
Answer
Correct option: A.
Heating $NH_4NO_2$
a
$(NH_ 4)_2Cr_2O_7 \to N_2 + Cr_2O_3 + 4H_2O$
$(NH_ 4)_2Cr_2O_7 \to N_2 + Cr_2O_3 + 4H_2O$
$NH_4NO_2 \to N_2 + H_2O$
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