MCQ
$(NH_4)_2Cr_2O_7$ on heating gives :
- A$ N_2O$
- B$NH_3$
- C$NO_2$
- D$N_2$
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$A + B$ $\rightleftharpoons$ $C + D$ + heat
has reached equilibrium. The reaction may be made to proceed forward by
$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
