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Mole Concept And Stoichiometry — Chemistry STD 10 — Question

ICSE BoardEnglish MediumSTD 10ChemistryMole Concept And Stoichiometry3 Marks
Question
Nitrogen and oxygen gas react as illustrated by the equation given below $: N_2 + O_2 \rightarrow 2NO$
Calculate the volume of each reacting gas required to produce $1400\ cm^3$ of nitric oxide.
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Answer

Given react ion is :
$N_2 + O_2 \rightarrow 2NO$
According to Gay $-$ Lussac's law in the above reaction $1$ volume of nitrogen combines with $1$ volume of oxygen to produce $2$ volumes of nitric oxide.
i .e. $N_2 + O_2 \rightarrow 2NO$
$1 \ vol. 1 \ vol. 2 \ vol.$
The volume of nitric oxide produced is $= 1400\ cm^3.$
Let the volumes of nitrogen and oxygen gases be $= x$
Then$, N_2 + O_2\rightarrow 2NO$
$ x \ \times \ 1400\ cm3$
So$, x + x = 1400$
$2x = 1400$
$x= 1400/ 2 = 700\ cm^3$
Hence the volumes of reacting gases i .e. nitrogen and oxygen is $700 \ cm^3$​​​​​​​ each.

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