MCQ
Nitrogen is obtained when $NaN{O_2}$ reacts with
- ✓$N{H_4}Cl$
- B$N{H_4}N{O_3}$
- C${(N{H_4})_2}C{O_3}$
- D$N{H_4}OH$
$N{H_4}N{O_2} \longrightarrow {N_2} + 2{H_2}O$
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$(I)$ $S_2O_4^{2-}$ $(II)$ $S_2O_5^{2-}$ $(III)$ $S_2O_6^{2-}$