- ✓$Zr, \,Ti$
- B$Mn,\, Fe$
- C$Fe, \,Co$
- D$Li,\, Na$
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(consider complete conversion)
(image) $\frac{{conc.\,HN{O_3}}}{{conc.\,{H_2}S{O_4}}}X$
the structure of the major product $'X'$ is
Precipitate $X$ is
$(A)$ $Fe _4\left[ Fe ( CN )_6\right]_3$
$(B)$ $Fe \left[ Fe ( CN )_6\right]$
$(C)$ $K _2 Fe \left[ Fe ( CN )_6\right]$
$(D)$ $KFe \left[ Fe ( CN )_6\right]$
Among the following, the brown ring is due to the formation of
$(A)$ $\left[ Fe ( NO )_2\left( SO _4\right)_2\right]^{2-}$
$(B)$ $\left[ Fe ( NO )_2\left( H _2 O \right)_4\right]^{3+}$
$(C)$ $\left[ Fe ( NO )_4\left( SO _4\right)_2\right]$
$(D)$ $\left[ Fe ( NO )\left( H _2 O \right)_5\right]^{2+}$
$(I)$ both the complexes can be high spin
$(II)$ $Ni(II)$ complex can very rarely be low spin.
$(III)$ with strong field ligands, $Mn(II)$ complexes can be low spin.
$(IV)$ aqueous solution of $Mn ( II )$ ions is yellow in color.
