- A$22$
- ✓$24$
- C$20$
- D$28$
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$C_{(graphite)} +O_2(g) \rightarrow CO_2(g)\,;$
$\Delta _rH^o=-395.5 \, kJ\,mol^{-1}$
$H_2 (g) + \frac{1}{2} O_2 (g) \rightarrow H_2O(l)\,;$ $\Delta _rH^o =-285.8\, kJ\, mol^{-1}$
$CO_2(g) + 2H_2O(l) \rightarrow CH_4(g) + 2O_2(g)\,;$
$\Delta _rH^o = + 890.3\, kJ\, mol^{-1}$
Based on the above thermochemical equations, the value of, $\Delta _rH^o $ at $298\, K$ for the reaction
$C_{(graphite)} + 2H_2(g) \rightarrow CH_4(g) $ will be for $\Delta_{r} H^{\circ}$ ........... $kJ \,mol^{-1}$

$(i)\, LiF > LiCl > LiBr > LiI$
$(ii)\, CaCl_2 < FeCl_2 < FeCl_3$
$(iii)Hg_2Cl_2 > HgCl_2$
$(iv)\, ZnCl_2 < CdCl_2 < HgCl_2$
$(v) CuCl < AgCl < AuCl$
$(vi) AlN > Al_2O_3 > AlF_3$
$(vii) CaF_2 < CaCl_2 < CaBr_2 < CaI_2$
