MCQ
Number of orbitats in $h$ sub-shell is
- ✓$11$
- B$15$
- C$17$
- D$19$
$l$ = $0$ $1$ $2$ $3$ $4$ $5$
Number of orbitals $ = 5 \times 2 + 1 = 11$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$SO _{2} Cl _{2}+2 H _{2} O \rightarrow H _{2} SO _{4}+2 HCl$ $16\,moles$ of $NaOH$ is required for the complete neutralisation of the resultant acidic mixture. The number of moles of $SO _{2} Cl _{2}$ used is.