MCQ
Number of $S - S$ bond is $H_2S_nO_6$
- A$n$
- ✓$(n - 1)$
- C$(n - 2)$
- D$(n + 1)$
Hence option $\mathrm{B}$ is correct.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$V^{+4},\,Ni^{+2},\, Ti^{+3}, \,Co^{+2}, \,Fe^{+3}, \,Cu^{+2}$
| Column $-I$ | Column $-II$ |
| (Atomic number) | (Position of element in Periodic table) |
| $(A)$ $Z = 37$ | $(P)$ $p-$ block |
| $(B)$ $Z = 42$ | $(Q)$ $f-$ block |
| $(C)$ $Z = 34$ | $(R)$ $d-$ block |
| $(D)$ $Z = 92$ | $(S)$ $s-$ block |
