MCQ
Number of $S - S$ bond is $H_2S_nO_6$
- A$n$
- ✓$(n - 1)$
- C$(n - 2)$
- D$(n + 1)$
Hence option $\mathrm{B}$ is correct.
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$(A)$ $n =3,1=0, m =0$
$(B)$ $n =4, l =0, m =0$
$(C)$ $n =3, l =1, m =0$
$(D)$ $n =3, l =2, m =1$
The correct option for the order is :

$H _{2}+\frac{1}{2} O _{2} \rightarrow H _{2} O , \cdots \cdots( ii )$ $\Delta H =-\,287.3 \,kJ\,mol ^{-1}$
$2 CO _{2}+3 H _{2} O \rightarrow C _{2} H _{5} OH +3 O _{2} \cdots \cdots ( iii )$; $ \Delta H =1366.8 \,kJ\,mol ^{-1}$
Find the standard enthalpy of formation of $C _{2} H _{5} OH (1)$