Question

Obtain the original frequency distribution from the following data :
Mid value $250$ $350$ $450$ $550$ $650$ $750$ Total
Frequency $20$ $80$ $80$ $40$ $60$ $20$ $300$

Answer

The difference between two successive mid values is $100.$ Therefore class length $c = 100$ and using the formulae Lower limit $=$ Mid value  $-\frac{c}{2} ;$Upper limit = Mid value $+\frac{c}{2}$ we obtain the class limits for each mid value. We get the original frequency distribution as follows :
Mid value Class limits Original frequency distribution
Lower limit $=$ mid value  $–\frac{}100{2}$ Upper limit $=$ Mid value $+\frac{100}{2}$ Class Frequency
f
$250$ $200$ $300$ $200 -300$ $20$
$350$ $300$ $400$ $300 -400$ $80$
$450$ $400$ $500$ $400 -500$ $80$
$550$ $500$ $600$ $500 -600$ $40$
$650$ $600$ $700$ $600 -700$ $60$
$750$ $700$ $800$ $700 -800$ $20$
  - - Total $300$

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