Question
Of $\frac{2}{3}$ and $\frac{5}{9},$which is greater and by how much?
✓
Answer
$\frac{2}{3}\text{ and }\frac{5}{9}$
LCM of 3 and 9 = 9
$\frac{2}{3}=\frac{2\times3}{3\times3}=\frac{6}{9}$
$\therefore\frac{2}{3}$ is greater than $\frac{5}{9}$
or $\frac{2}{3}$ is greater than $\frac{5}{9}$
and $\frac{6}{9}-\frac{5}{9}=\frac{1}{9}$
$\therefore\frac{2}{3}$ is greater than $\frac{5}{9}\text{ by }\frac{1}{9}$
LCM of 3 and 9 = 9
$\frac{2}{3}=\frac{2\times3}{3\times3}=\frac{6}{9}$
$\therefore\frac{2}{3}$ is greater than $\frac{5}{9}$
or $\frac{2}{3}$ is greater than $\frac{5}{9}$
and $\frac{6}{9}-\frac{5}{9}=\frac{1}{9}$
$\therefore\frac{2}{3}$ is greater than $\frac{5}{9}\text{ by }\frac{1}{9}$
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