MCQ
On adding water to $BiC{l_3}$ solution in $HCl$, the compound produced is
- A$B{i_2}{O_3}$
- B$Bi{(OH)_3}$
- ✓$BiOCl$
- D$BiOC{l_2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$[Co(en)_3]\,[Cr(C_2O_4)_3]$
$[Cu(NH_3)_4]\, [CuCl_4]$
$[Ni(en)_3]\,[Co(NO_2)_6]$
${{C}_{3}}{{H}_{7}}OH\underset{160-{{180}\,^{o}}C}{\mathop{\xrightarrow{Conc.{{H}_{2}}S{{O}_{4}}}}}\,X\underset{{}}{\mathop{\xrightarrow{B{{r}_{2}}}}}\,Y\underset{Alc.KOH}{\mathop{\xrightarrow{\text{Excess of}}}}\,Z$
$\mathop { - CH{{(C{H_3})}_2}}\limits_1 \,\,\,\,\,\,\,\,\,\,\,\mathop { - C{H_2}C{H_2}Br}\limits_2 \,\,\,\,\,\,\,\,\,\,\mathop{ - C{H_2}Br}\limits_3 \,\,\,\,\,\,\,\,\,\mathop{ - C{{(C{H_3})}_3}}\limits_4$
$I = II = III = IV$
$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\xrightarrow{{{C_6}{H_5}COOOH}}\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}}
\end{array}$
The above reaction is known as :
$C{H_3}COOH\xrightarrow{{LiAl{H_4}}}A\mathop {\xrightarrow{{{H^ + }}}}\limits_{443\,K} B\xrightarrow{{B{r_2}}}C\mathop {\xrightarrow{{alc.}}}\limits_{KOH} D$